Difference between revisions of "2006 AMC 12A Problems/Problem 1"

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== Solution ==
 
== Solution ==
  
The <math>5</math> sandwiches cost <math>5\cdot 3=15</math> dollars.  The <math>8</math> sodas cost <math>8\cdot 2=16</math> dollars.  In total, the purchase costs <math>15+16=31</math> dollars.
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The <math>5</math> sandwiches cost <math>5\cdot 3=15</math> dollars.  The <math>8</math> sodas cost <math>8\cdot 2=16</math> dollars.  In total, the purchase costs <math>15+16=31</math> dollars.  The answer is A.
  
 
== See also ==
 
== See also ==
 
* [[2006 AMC 12A Problems]]
 
* [[2006 AMC 12A Problems]]

Revision as of 20:59, 11 July 2006

Problem

Sandwiches at Joe's Fast Food cost $3$ each and sodas cost $2$ each. How many dollars will it cost to purchase $5$ sandwiches and $8$ sodas?

$\mathrm{(A) \ } 31\qquad \mathrm{(B) \ } 32\qquad \mathrm{(C) \ } 33\qquad \mathrm{(D) \ } 34$

$\mathrm{(E) \ } 35$

Solution

The $5$ sandwiches cost $5\cdot 3=15$ dollars. The $8$ sodas cost $8\cdot 2=16$ dollars. In total, the purchase costs $15+16=31$ dollars. The answer is A.

See also