Difference between revisions of "2016 AMC 10B Problems/Problem 19"
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\textbf{(D)}~\frac{10}{91}\qquad | \textbf{(D)}~\frac{10}{91}\qquad | ||
\textbf{(E)}~\frac19</math> | \textbf{(E)}~\frac19</math> | ||
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+ | ==Solution== | ||
+ | <math>\textbf{(D)}~\frac{10}{91}</math> | ||
+ | |||
+ | solution by ngeorge |
Revision as of 10:29, 21 February 2016
Problem
Rectangle has
and
. Point
lies on
so that
, point
lies on
so that
. and point
lies on
so that
. Segments
and
intersect
at
and
, respectively. What is the value of
?
Solution
solution by ngeorge