Difference between revisions of "2000 AMC 12 Problems/Problem 3"

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<math>\displaystyle x=\frac{25}{16}\cdot32= 50 \Rightarrow B </math>
 
<math>\displaystyle x=\frac{25}{16}\cdot32= 50 \Rightarrow B </math>
  
== See Also ==
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== See also ==
[[2000 AMC 12 Problems]]
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* [[2000 AMC 12 Problems]]
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*[[2000 AMC 12/Problem 2|Previous Problem]]
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*[[2000 AMC 12/Problem 4|Next problem]]
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[[Category:Introductory Algebra Problems]]

Revision as of 18:22, 5 November 2006

Problem

Each day, Jenny ate $20%$ (Error compiling LaTeX. Unknown error_msg) of the jellybeans that were in her jar at the beginning of that day. At the end of the second day, $32$ remained. How many jellybeans were in the jar originally?

$\mathrm{(A) \ 40 } \qquad \mathrm{(B) \ 50 } \qquad \mathrm{(C) \ 55 } \qquad \mathrm{(D) \ 60 } \qquad \mathrm{(E) \ 75 }$

Solution

Since Jenny eats $20%$ (Error compiling LaTeX. Unknown error_msg) of her jelly beans per day, $80%=\frac{4}{5}$ (Error compiling LaTeX. Unknown error_msg) of her jelly beans remain after one day.

Let $x$ be the number of jelly beans in the jar originally.

$\frac{4}{5}\cdot\frac{4}{5}\cdot x=32$

$\frac{16}{25}\cdot x=32$

$\displaystyle x=\frac{25}{16}\cdot32= 50 \Rightarrow B$

See also