Difference between revisions of "2006 AMC 10B Problems/Problem 19"
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== See Also == | == See Also == | ||
*[[2006 AMC 10B Problems]] | *[[2006 AMC 10B Problems]] | ||
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+ | *[[2006 AMC 10B Problems/Problem 18|Previous Problem]] | ||
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+ | *[[2006 AMC 10B Problems/Problem 20|Next Problem]] |
Revision as of 15:03, 2 August 2006
Problem
A circle of radius is centered at
. Square
has side length
. Sides
and
are extended past
to meet the circle at
and
, respectively. What is the area of the shaded region in the figure, which is bounded by
,
, and the minor arc connecting
and
?
Solution
The shaded area is equivilant to the area of sector , minus the area of triangle
plus the area of triangle
.
Using the Pythagorean Theorem:
Clearly, and
are
triangles with
.
Since is a square,
.
can be found by doing some subtraction of angles.
So, the area of sector is
.
The area of triangle is
.
Since ,
.
So, the area of triangle is
.
Therefore, the shaded area is