Difference between revisions of "2004 AMC 8 Problems/Problem 1"
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== Solution == | == Solution == | ||
We set up the proportion <math>\frac{12 \text{cm}}{72 \text{km}}=\frac{17 \text{cm}}{x \text{km}}</math>. Thus <math>x=102 \Rightarrow \boxed{\textbf{(B)}\ 102}</math> | We set up the proportion <math>\frac{12 \text{cm}}{72 \text{km}}=\frac{17 \text{cm}}{x \text{km}}</math>. Thus <math>x=102 \Rightarrow \boxed{\textbf{(B)}\ 102}</math> | ||
+ | |||
+ | == Solution 2 == | ||
+ | Since we know | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2004|before=First <br />Question|num-a=2}} | {{AMC8 box|year=2004|before=First <br />Question|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 04:18, 24 July 2018
Contents
Problem
On a map, a -centimeter length represents
kilometers. How many kilometers does a
-centimeter length represent?
Solution
We set up the proportion . Thus
Solution 2
Since we know
See Also
2004 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
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All AJHSME/AMC 8 Problems and Solutions |
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