Difference between revisions of "University of South Carolina High School Math Contest/1993 Exam/Problem 20"
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We have <math>(1+1)(1+2)(1+3)(1+4)(1+5)(1+6)-1</math> (The <math>-1</math> since we have one less set). This is <math>7!-1=5039</math>. | We have <math>(1+1)(1+2)(1+3)(1+4)(1+5)(1+6)-1</math> (The <math>-1</math> since we have one less set). This is <math>7!-1=5039</math>. | ||
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− | * [[University of South Carolina High School Math Contest/1993 Exam]] | + | |
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+ | [[Category:Intermediate Combinatorics Problems]] |
Revision as of 10:53, 23 July 2006
Problem
Let be the 63 nonempty subsets of . For each of these sets , let denote the product of all the elements in . Then what is the value of ?
Solution
We have (The since we have one less set). This is .