Difference between revisions of "University of South Carolina High School Math Contest/1993 Exam/Problem 10"
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== Solution == | == Solution == | ||
− | If we construct right triangles for each pair of arguments (<math>\arcsin, \arccos</math> and <math>\arctan, arccot</math>), we see that the sum of the angles is <math>90^\circ+90^\circ=\pi</math>. | + | If we construct right triangles for each pair of arguments (<math>\arcsin, \arccos</math> and <math>\arctan, \arccot</math>), we see that the sum of the angles is <math>90^\circ+90^\circ=\pi</math>. |
== See also == | == See also == |
Revision as of 20:36, 22 July 2006
Problem
Arcsin(1/3) + Arccos(1/3) + Arctan(1/3) + Arccot(1/3) =
![$\mathrm{(A) \ }\pi \qquad \mathrm{(B) \ }\pi/2 \qquad \mathrm{(C) \ }\pi/3 \qquad \mathrm{(D) \ }2\pi/3 \qquad \mathrm{(E) \ }3/\pi/4$](http://latex.artofproblemsolving.com/9/7/b/97b0fa52186af1028b00c9f5a690827a039634be.png)
Solution
If we construct right triangles for each pair of arguments ( and $\arctan, \arccot$ (Error compiling LaTeX. Unknown error_msg)), we see that the sum of the angles is
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