Difference between revisions of "University of South Carolina High School Math Contest/1993 Exam/Problem 11"
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The probability is <math>\frac{3!+2!+1!}{4!}=\frac{3}{8}</math>. | The probability is <math>\frac{3!+2!+1!}{4!}=\frac{3}{8}</math>. | ||
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Revision as of 17:18, 17 August 2006
Problem
Suppose that 4 cards labeled 1 to 4 are placed randomly into 4 boxes also labeled 1 to 4, one card per box. What is the probability that no card gets placed into a box having the same label as the card?
Solution
The probability is .
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