Difference between revisions of "1994 AHSME Problems/Problem 6"
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We work backwards to find <math>a</math>. | We work backwards to find <math>a</math>. | ||
− | <cmath>d+0=1 | + | <cmath> d+0=1\implies d=1</cmath> |
+ | <cmath>c+1=0\implies c=-1</cmath> | ||
+ | <cmath> b+(-1)=1\implies b=2</cmath> | ||
+ | <cmath>a+2=-1\implies a=\boxed{\textbf{(A)}-3.}</cmath> | ||
--Solution by [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=200685 TheMaskedMagician] | --Solution by [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=200685 TheMaskedMagician] |
Revision as of 04:11, 18 February 2018
Problem
In the sequence
each term is the sum of the two terms to its left. Find
.
Solution
We work backwards to find .
--Solution by TheMaskedMagician