Difference between revisions of "2017 AMC 10B Problems/Problem 25"
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==Problem== | ==Problem== | ||
Last year Isabella took <math>7</math> math tests and received <math>7</math> different scores, each an integer between <math>91</math> and <math>100</math>, inclusive. After each test she noticed that the average of her test scores was an integer. Her score on the seventh test was <math>95</math>. What was her score on the sixth test? | Last year Isabella took <math>7</math> math tests and received <math>7</math> different scores, each an integer between <math>91</math> and <math>100</math>, inclusive. After each test she noticed that the average of her test scores was an integer. Her score on the seventh test was <math>95</math>. What was her score on the sixth test? | ||
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+ | <math>\textbf{(A)}\ 92\qquad\textbf{(B)}\ 94\qquad\textbf{(C)}\ 96\qquad\textbf{(D)}\ 98\qquad\textbf{(E)}\ 100</math> | ||
==Cheap Solution== | ==Cheap Solution== | ||
By inspection, the sequences <math>91,93,92,96,98,100,95</math> and <math>93,91,92,96,98,100,95</math> work, so the answer is $\boxed{\textbf{E } 100}. | By inspection, the sequences <math>91,93,92,96,98,100,95</math> and <math>93,91,92,96,98,100,95</math> work, so the answer is $\boxed{\textbf{E } 100}. |
Revision as of 09:01, 16 February 2017
Problem
Last year Isabella took math tests and received different scores, each an integer between and , inclusive. After each test she noticed that the average of her test scores was an integer. Her score on the seventh test was . What was her score on the sixth test?
Cheap Solution
By inspection, the sequences and work, so the answer is $\boxed{\textbf{E } 100}.