Difference between revisions of "2017 AMC 10B Problems/Problem 25"

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==Problem==
 
==Problem==
 
Last year Isabella took <math>7</math> math tests and received <math>7</math> different scores, each an integer between <math>91</math> and <math>100</math>, inclusive. After each test she noticed that the average of her test scores was an integer. Her score on the seventh test was <math>95</math>. What was her score on the sixth test?
 
Last year Isabella took <math>7</math> math tests and received <math>7</math> different scores, each an integer between <math>91</math> and <math>100</math>, inclusive. After each test she noticed that the average of her test scores was an integer. Her score on the seventh test was <math>95</math>. What was her score on the sixth test?
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<math>\textbf{(A)}\ 92\qquad\textbf{(B)}\ 94\qquad\textbf{(C)}\ 96\qquad\textbf{(D)}\ 98\qquad\textbf{(E)}\ 100</math>
  
 
==Cheap Solution==
 
==Cheap Solution==
  
 
By inspection, the sequences <math>91,93,92,96,98,100,95</math> and <math>93,91,92,96,98,100,95</math> work, so the answer is $\boxed{\textbf{E } 100}.
 
By inspection, the sequences <math>91,93,92,96,98,100,95</math> and <math>93,91,92,96,98,100,95</math> work, so the answer is $\boxed{\textbf{E } 100}.

Revision as of 09:01, 16 February 2017

Problem

Last year Isabella took $7$ math tests and received $7$ different scores, each an integer between $91$ and $100$, inclusive. After each test she noticed that the average of her test scores was an integer. Her score on the seventh test was $95$. What was her score on the sixth test?

$\textbf{(A)}\ 92\qquad\textbf{(B)}\ 94\qquad\textbf{(C)}\ 96\qquad\textbf{(D)}\ 98\qquad\textbf{(E)}\ 100$

Cheap Solution

By inspection, the sequences $91,93,92,96,98,100,95$ and $93,91,92,96,98,100,95$ work, so the answer is $\boxed{\textbf{E } 100}.