Difference between revisions of "2018 AMC 10A Problems/Problem 4"
(→See also) |
m (→See also) |
||
| Line 24: | Line 24: | ||
==See also== | ==See also== | ||
| − | {{AMC10 box|year=2018|ab=A| | + | {{AMC10 box|year=2018|ab=A|num_a=3|num_b=5} |
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 16:34, 8 February 2018
Problem
How many ways can a student schedule 3 mathematics courses -- algebra, geometry, and number theory -- in a 6-period day if no two mathematics courses can be taken in consecutive periods? (What courses the student takes during the other 3 periods is of no concern here.)
Solution
We must place the classes into the periods such that no two balls are in the same period or in consecutive period.
Ignoring distinguishability, we can thus list out the ways that three periods can be chosen for the classes, when periods cannot be consecutive:
Periods 
Periods 
Periods 
Periods 
There are 
ways to place 
nondistinguishable classes into 
periods such that no two classes are in consecutive periods. For each of these ways, there are 
orderings of the classes among themselves.
Therefore, there are 
ways to choose the classes.
See also
{{AMC10 box|year=2018|ab=A|num_a=3|num_b=5}
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
