Difference between revisions of "2019 AMC 10A Problems/Problem 1"
(Created page with "The first part can be rewritten as <cmath>2^{0^{1}}=2^{0}=1</cmath>. The second part is <cmath>(1^{1})^{9}=1^{9}=1</cmath>. Adding these up gives \fbox{(C) <cmath>2</cmath>}") |
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The first part can be rewritten as <cmath>2^{0^{1}}=2^{0}=1</cmath>. | The first part can be rewritten as <cmath>2^{0^{1}}=2^{0}=1</cmath>. | ||
| − | The second part is <cmath>(1^{1})^{9}=1^{9}=1</cmath>. Adding these up gives | + | The second part is <cmath>(1^{1})^{9}=1^{9}=1</cmath>. Adding these up gives (C) <cmath>2</cmath> |
Revision as of 15:00, 9 February 2019
The first part can be rewritten as ![\[2^{0^{1}}=2^{0}=1\]](http://latex.artofproblemsolving.com/7/e/2/7e2e77e5a74459fb40e84717608fa12cf0c6732b.png)
.
The second part is ![\[(1^{1})^{9}=1^{9}=1\]](http://latex.artofproblemsolving.com/c/a/3/ca33597adbfe49478e6dd72ab9163f8b88cdbd4a.png)
. Adding these up gives (C) ![\[2\]](http://latex.artofproblemsolving.com/c/e/d/ced7949d3bc8ef8c7a09c4ec819f30277b50d2c2.png)
