Difference between revisions of "2019 AMC 12B Problems/Problem 1"

Latest revision as of 12:13, 14 February 2019

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-==Problem==
+#REDIRECT[[2019_AMC_10B_Problems/Problem_1]]
-==Solution==
-Let the first jar's volume be <math>A</math> and the second's be <math>B</math>. It is given that <math>\frac{3}{4}A=\frac{5}{6}B</math>. We find that <math>\frac{B}{A}=\frac{3/4}{5/6}=\boxed{\frac{9}{10}}.</math>
-We already know that this is the ratio of smaller to larger volume because it is less than <math>1.</math>
---mguempel
-==See Also==
-{{AMC12 box|year=2019|ab=B|before=First Problem|num-a=2}}
-{{MAA Notice}}