Difference between revisions of "2006 Canadian MO Problems/Problem 4"
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(b) Find the maximum number of cycle triplets possible. | (b) Find the maximum number of cycle triplets possible. | ||
==Solution== | ==Solution== | ||
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{{solution}} | {{solution}} | ||
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*[[2006 Canadian MO]] | *[[2006 Canadian MO]] | ||
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| + | {{CanadaMO box|year=2006|num-b=3|num-a=5}} | ||
Revision as of 18:58, 7 February 2007
Problem
Consider a round robin tournament with 
teams, where two teams play exactly one match and there are no ties. We say that the teams 
, 
, and 
form a cycle triplet if beats , beats , and beats .
(a) Find the minimum number of cycle triplets possible.
(b) Find the maximum number of cycle triplets possible.
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See also
| 2006 Canadian MO (Problems) | ||
| Preceded by Problem 3 |
1 • 2 • 3 • 4 • 5 | Followed by Problem 5 |
