Difference between revisions of "2019 CIME I Problems/Problem 13"
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Suppose <math>\text{P}</math> is a monic polynomial whose roots <math>a</math>, <math>b</math>, and <math>c</math> are real numbers, at least two of which are positive, that satisfy the relation <cmath>a(a-b)=b(b-c)=c(c-a)=1.</cmath> Find the greatest integer less than or equal to <math>100|P(\sqrt{3})|</math>. | Suppose <math>\text{P}</math> is a monic polynomial whose roots <math>a</math>, <math>b</math>, and <math>c</math> are real numbers, at least two of which are positive, that satisfy the relation <cmath>a(a-b)=b(b-c)=c(c-a)=1.</cmath> Find the greatest integer less than or equal to <math>100|P(\sqrt{3})|</math>. | ||
+ | ==Solution== | ||
+ | We don't know yet. | ||
+ | |||
+ | ==See also== | ||
{{CIME box|year=2019|n=I|num-b=12|num-a=14}} | {{CIME box|year=2019|n=I|num-b=12|num-a=14}} | ||
[[Category:Intermediate Algebra Problems]] | [[Category:Intermediate Algebra Problems]] | ||
{{MAC Notice}} | {{MAC Notice}} |
Revision as of 17:10, 3 October 2020
Suppose is a monic polynomial whose roots
,
, and
are real numbers, at least two of which are positive, that satisfy the relation
Find the greatest integer less than or equal to
.
Solution
We don't know yet.
See also
2019 CIME I (Problems • Answer Key • Resources) | ||
Preceded by Problem 12 |
Followed by Problem 14 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All CIME Problems and Solutions |
The problems on this page are copyrighted by the MAC's Christmas Mathematics Competitions.