Difference between revisions of "User:Vincentwant"

Revision as of 19:03, 10 December 2020

I am listing the prime factorizations of upcoming years. I am doing this because some math competitions often involve the factorization of the year it was assessed. Thanks to Po-Shen Loh for giving me this idea. (Factors include 1 and the number itself.)

$2021 = 43\cdot 47 \text{ (has 4 factors)}$

$2022 = 2\cdot 3\cdot 337 \text{ (has 8 factors)}$

$2023 = 7\cdot 17^2 \text{ (has 6 factors)}$

$2024 = 2^3\cdot 11\cdot 23 \text{ (has 12 factors)}$

$2025 = 3^4\cdot 5^2 \text{ (has 15 factors)}$

$2026 = 2\cdot 1013 \text{ (has 4 factors)}$

$2027 = \text{2027 is prime (has 2 factors)}$

$2028 = 2^2\cdot 3\cdot 13^2 \text{ (has 18 factors)}$

$2029 = \text{2029 is prime (has 2 factors)}$

$2030 = 2\cdot 5\cdot 7\cdot 29 \text{ (has 16 factors)}$

$2031 = 3\cdot 677 \text{ (has 4 factors)}$

$2032 = 2^4\cdot 127 \text{ (has 10 factors)}$

$2033 = 19\cdot 107 \text{ (has 4 factors)}$

$2034 = 2\cdot 3^2\cdot 113 \text{ (has 12 factors)}$

$2035 = 5\cdot 11\cdot 37 \text{ (has 8 factors)}$

$2036 = 2^2\cdot 509 \text{ (has 6 factors)}$

$2037 = 3\cdot 7\cdot 97 \text{ (has 8 factors)}$

$2038 = 2\cdot 1019 \text{ (has 4 factors)}$

$2039 = \text{2039 is prime (has 2 factors)}$

$2040 = 2^3\cdot 3\cdot 5\cdot 17 \text{ (has 32 factors)}$

$2041 = 13\cdot 157 \text{ (has 4 factors)}$

$2042 = 2\cdot 1021 \text{ (has 4 factors)}$

$2043 = 3^2\cdot 227 \text{ (has 6 factors)}$

$2044 = 2^2\cdot 7\cdot 73 \text{ (has 12 factors)}$

$2045 = 5\cdot 409 \text{ (has 4 factors)}$

$2046 = 2\cdot 3\cdot 11\cdot 31 \text{ (has 16 factors)}$

$2047 = 23\cdot 89 \text{ (has 4 factors)}$

$2048 = 2^{11} \text{ (has 12 factors)}$

Revision as of 19:03, 10 December 2020 (view source) Vincentwant (talk \| contribs) ← Older edit		Revision as of 19:03, 10 December 2020 (view source) Vincentwant (talk \| contribs) Newer edit →
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	<math>2047 = 23\cdot 89 \text{ (has 4 factors)}</math>		<math>2047 = 23\cdot 89 \text{ (has 4 factors)}</math>

−	<math>2048 = 2^{11} \text{has 12 factors}</math>	+	<math>2048 = 2^{11} \text{ (has 12 factors)}</math>

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Difference between revisions of "User:Vincentwant"

Revision as of 19:03, 10 December 2020