Difference between revisions of "1955 AHSME Problems/Problem 39"
(Wrote a Solution for this problem, since it didn't have one.) |
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<cmath>y = \frac{p^2}{4} - \frac{p^2}{2} + q</cmath> | <cmath>y = \frac{p^2}{4} - \frac{p^2}{2} + q</cmath> | ||
<cmath>0 = \frac{p^2}{4} - \frac{2p^2}{4} + q</cmath> | <cmath>0 = \frac{p^2}{4} - \frac{2p^2}{4} + q</cmath> | ||
− | < | + | <cmath>0 = \frac{-p^2}{4} + q</cmath> |
<cmath>q = \frac{p^2}{4} = \boxed{B}</cmath> | <cmath>q = \frac{p^2}{4} = \boxed{B}</cmath> | ||
~JustinLee2017 | ~JustinLee2017 |
Revision as of 18:37, 12 February 2021
Solution
The least possible value of is given at the
coordinate of the vertex. The
- coordinate is given by
. Plugging this into the quadratic, we get
~JustinLee2017