Difference between revisions of "2008 AMC 10A Problems/Problem 7"
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==Problem== | ==Problem== | ||
The fraction | The fraction | ||
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<cmath>\frac{\left(3^{2008}\right)^2-\left(3^{2006}\right)^2}{\left(3^{2007}\right)^2-\left(3^{2005}\right)^2}</cmath> | <cmath>\frac{\left(3^{2008}\right)^2-\left(3^{2006}\right)^2}{\left(3^{2007}\right)^2-\left(3^{2005}\right)^2}</cmath> | ||
simplifies to which of the following? | simplifies to which of the following? |
Revision as of 17:00, 1 May 2021
Contents
[hide]Problem
The fraction
simplifies to which of the following?
Solution
Simplifying, we get Factoring out on the top and factoring out on the bottom gives us Canceling out gives us
Solution 2
Using Difference of Squares, becomes
See also
2008 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 6 |
Followed by Problem 8 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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