Difference between revisions of "2021 JMPSC Accuracy Problems/Problem 1"
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− | + | We use the fact that 27 = 2^3<math> to conclude that the only multiples of </math>3<math> that are factors of </math>27<math> are </math>3<math>, </math>9<math>, and </math>27<math>. Thus, our answer is </math>3+9+27=\boxed{39)$ | |
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+ | ~Bradygho |
Revision as of 20:56, 10 July 2021
Problem
Find the sum of all positive multiples of that are factors of
Solution
We use the fact that 27 = 2^332739273+9+27=\boxed{39)$
~Bradygho