Difference between revisions of "2021 JMPSC Accuracy Problems/Problem 1"

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== Solution ==
 
== Solution ==
  
We use the fact that <math>27 = 2^3</math> to conclude that the only multiples of <math>3</math> that are factors of <math>27</math> are <math>3</math>, <math>9</math>, and <math>27</math>. Thus, our answer is <math>3 + 9 + 27 = 39</math>.
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We use the fact that <math>27 = 2^3</math> to conclude that the only multiples of <math>3</math> that are factors of <math>27</math> are <math>3</math>, <math>9</math>, and <math>27</math>. Thus, our answer is <math>3 + 9 + 27 = \boxed{39}</math>.
  
 
~Bradygho
 
~Bradygho

Revision as of 21:01, 10 July 2021

Problem

Find the sum of all positive multiples of $3$ that are factors of $27.$

Solution

We use the fact that $27 = 2^3$ to conclude that the only multiples of $3$ that are factors of $27$ are $3$, $9$, and $27$. Thus, our answer is $3 + 9 + 27 = \boxed{39}$.

~Bradygho