Difference between revisions of "2021 JMPSC Sprint Problems/Problem 2"
| Line 9: | Line 9: | ||
-OofPirate | -OofPirate | ||
| + | == Solution 2 == | ||
| + | You want as many quarters in order to cut down on the number of coins. The most amount of quarters you can have is <math>11</math>. Since you can't use three cents on anything other than pennies, the remaining coins are <math>3</math> pennies. Therefore <math>11+3=14</math> | ||
==See also== | ==See also== | ||
Revision as of 09:09, 12 July 2021
Contents
Problem
Brady has an unlimited supply of quarters ($0.25), dimes ($0.10), nickels ($0.05), and pennies ($0.01). What is the least number (quantity, not type) of coins Brady can use to pay off $
?
Solution
It is generally best to use the smallest number of coins with the most value, specifically the quarters, for taking away a big chunk of the problem. We are able to fit 
quarters, or 
into 
. That only leaves 
cents. We cannot put any nickels nor dimes, therefore we require three pennies to get a total of .
The least number of coins Brady can use to pay off will be 
coins.
-OofPirate
Solution 2
You want as many quarters in order to cut down on the number of coins. The most amount of quarters you can have is . Since you can't use three cents on anything other than pennies, the remaining coins are pennies. Therefore 
See also
The problems on this page are copyrighted by the Junior Mathematicians' Problem Solving Competition. 
