Difference between revisions of "2004 AMC 10A Problems/Problem 1"

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There are 6 people to split the <math>1500</math> dollars among, so each person must raise <math>\frac{1500}6=250</math> dollars.  <math>\Rightarrow\mathrm{(A)}</math>
 
There are 6 people to split the <math>1500</math> dollars among, so each person must raise <math>\frac{1500}6=250</math> dollars.  <math>\Rightarrow\mathrm{(A)}</math>
  
==See also==
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== See also ==
*[[2004 AMC 10A Problems]]
 
 
 
 
{{AMC10 box|year=2004|ab=A|before=First Question|num-a=2}}
 
{{AMC10 box|year=2004|ab=A|before=First Question|num-a=2}}
  
 
[[Category:Introductory Algebra Problems]]
 
[[Category:Introductory Algebra Problems]]

Revision as of 01:37, 11 September 2007

Problem

You and five friends need to raise $1500$ dollars in donations for a charity, dividing the fundraising equally. How many dollars will each of you need to raise?

$\mathrm{(A) \ } 250\qquad \mathrm{(B) \ } 300 \qquad \mathrm{(C) \ } 1500 \qquad \mathrm{(D) \ } 7500 \qquad \mathrm{(E) \ } 9000$

Solution

There are 6 people to split the $1500$ dollars among, so each person must raise $\frac{1500}6=250$ dollars. $\Rightarrow\mathrm{(A)}$

See also

2004 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
First Question
Followed by
Problem 2
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All AMC 10 Problems and Solutions