Difference between revisions of "User:Temperal/Introductory Proportion"

Revision as of 15:20, 16 September 2007

Suppose $\displaystyle \frac{1}{20}$ is either x or y in the following system:

$\begin{cases} xy=\frac{1}{k}\\ x=ky \end{cases}$

Find the possible values of k.

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if $x=\frac{1} {20}$ , then $\frac{y} {20} = \frac{1} {k}$

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−	if <math>x=\frac{1} {20}</math>, then <math> \frac{y} {20} = \frac{1} {k}~~</math> and <math>ky=20~~</math>	+	if <math>x=\frac{1} {20}</math>, then <math> \frac{y} {20} = \frac{1} {k}</math>