Difference between revisions of "1996 AIME Problems/Problem 2"

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== Problem ==
 
== Problem ==
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For each real number <math>x</math>, let <math>\lfloor x \rfloor</math> denote the greatest integer that does not exceed x. For how man positive integers <math>n</math> is it true that <math>n<1000</math> and that <math>\lfloor \log_{2} n \rfloor</math> is a positive even integer?
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== Solution ==
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n must satisfy these inequalities:
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<math>4\leq n <8</math>
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<math>16\leq n<32</math>
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<math>64\leq n<128</math>
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<math>256\leq n<512</math>
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There are 4 for the first inequality, 16 for the second, 64 for the third, and 256 for the fourth.
  
== Solution ==
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<math>4+16+64+256=340</math>
{{solution}}
 
 
== See also ==
 
== See also ==
 
* [[1996 AIME Problems/Problem 1 | Previous problem]]
 
* [[1996 AIME Problems/Problem 1 | Previous problem]]
 
* [[1996 AIME Problems/Problem 3 | Next problem]]
 
* [[1996 AIME Problems/Problem 3 | Next problem]]
 
* [[1996 AIME Problems]]
 
* [[1996 AIME Problems]]

Revision as of 13:56, 24 September 2007

Problem

For each real number $x$, let $\lfloor x \rfloor$ denote the greatest integer that does not exceed x. For how man positive integers $n$ is it true that $n<1000$ and that $\lfloor \log_{2} n \rfloor$ is a positive even integer?

Solution

n must satisfy these inequalities:


$4\leq n <8$

$16\leq n<32$

$64\leq n<128$

$256\leq n<512$

There are 4 for the first inequality, 16 for the second, 64 for the third, and 256 for the fourth.

$4+16+64+256=340$

See also