Difference between revisions of "1960 IMO Problems/Problem 4"
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Let <math>M_a</math>, <math>M_b</math>, and <math>M_c</math> be the midpoints of sides <math>\overline{BC}</math>, <math>\overline{CA}</math>, and <math>\overline{AB}</math>, respectively. Let <math>H_a</math>, <math>H_b</math>, and <math>H_c</math> be the feet of the altitudes from <math>A</math>, <math>B</math>, and <math>C</math> to their opposite sides, respectively. Since <math>\triangle ABC\sim\triangle M_bM_aC</math>, with <math>M_bM_a=\frac12 AB</math>, the distance from <math>M_a</math> to side <math>\overline{AC}</math> is <math>\frac{h_b}{2}</math>. | Let <math>M_a</math>, <math>M_b</math>, and <math>M_c</math> be the midpoints of sides <math>\overline{BC}</math>, <math>\overline{CA}</math>, and <math>\overline{AB}</math>, respectively. Let <math>H_a</math>, <math>H_b</math>, and <math>H_c</math> be the feet of the altitudes from <math>A</math>, <math>B</math>, and <math>C</math> to their opposite sides, respectively. Since <math>\triangle ABC\sim\triangle M_bM_aC</math>, with <math>M_bM_a=\frac12 AB</math>, the distance from <math>M_a</math> to side <math>\overline{AC}</math> is <math>\frac{h_b}{2}</math>. | ||
Revision as of 03:57, 17 August 2022
Problem
Construct triangle , given , (the altitudes from and ), and , the median from vertex .
Solution
https://youtu.be/M0_UdvxH890 [Video Solution] Let , , and be the midpoints of sides , , and , respectively. Let , , and be the feet of the altitudes from , , and to their opposite sides, respectively. Since , with , the distance from to side is .
Construct with length . Draw a circle centered at with radius . Construct the tangent to this circle through . lies on .
Draw a circle centered at with radius . Construct the tangent to this circle through . lies on . Then .
Construct the line parallel to so that the distance between and is and lies between these lines. lies on . Then .
See Also
1960 IMO (Problems) | ||
Preceded by Problem 3 |
1 • 2 • 3 • 4 • 5 • 6 • 7 | Followed by Problem 5 |