Difference between revisions of "2006 AMC 8 Problems/Problem 9"
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== Solution == | == Solution == | ||
We notice that the numerator in each fraction cancels out with the denominator of the one following it. This leaves us with only two numbers that didn't cancel: <math> \frac{2006}{2}=\boxed{\textbf{(C)}\ 1003} </math>. | We notice that the numerator in each fraction cancels out with the denominator of the one following it. This leaves us with only two numbers that didn't cancel: <math> \frac{2006}{2}=\boxed{\textbf{(C)}\ 1003} </math>. | ||
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| + | ==Video Solution== | ||
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| + | https://www.youtube.com/watch?v=HrlLDNc4u34 | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2006|num-b=8|num-a=10}} | {{AMC8 box|year=2006|num-b=8|num-a=10}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 14:15, 9 October 2022
Contents
Problem
What is the product of 
?
Solution
We notice that the numerator in each fraction cancels out with the denominator of the one following it. This leaves us with only two numbers that didn't cancel: 
.
Video Solution
https://www.youtube.com/watch?v=HrlLDNc4u34
See Also
| 2006 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 8 |
Followed by Problem 10 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
