Difference between revisions of "2008 AMC 8 Problems/Problem 1"

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==Solution==
 
==Solution==
If Susan spent 12 dollars, then twice that much on rides, then she spent <math>36</math> dollars in total. We subtract <math>36</math> from <math>50</math> to get <math>\boxed{\textbf{(B)}\ 14}</math>
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If Susan spent 12 dollars, then twice that much on rides, then she spent <math>12+12 \times 2=36</math> dollars in total. We subtract <math>36</math> from <math>50</math> to get <math>\boxed{\textbf{(B)}\ 14}</math>
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2008|before=First Problem|num-a=2}}
 
{{AMC8 box|year=2008|before=First Problem|num-a=2}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Latest revision as of 16:52, 6 November 2022

Problem

Susan had 50 dollars to spend at the carnival. She spent 12 dollars on food and twice as much on rides. How many dollars did she have left to spend?

$\textbf{(A)}\ 12 \qquad \textbf{(B)}\ 14 \qquad \textbf{(C)}\ 26 \qquad \textbf{(D)}\ 38 \qquad \textbf{(E)}\ 50$

Solution

If Susan spent 12 dollars, then twice that much on rides, then she spent $12+12 \times 2=36$ dollars in total. We subtract $36$ from $50$ to get $\boxed{\textbf{(B)}\ 14}$

See Also

2008 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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