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Difference between revisions of "2022 AMC 12B Problems"
(→Problem 3) |
(→Problem 1) |
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==Problem 1 == | ==Problem 1 == | ||
− | + | Define <math>x\diamond y</math> to be <math>|x-y|</math> for all real numbers <math>x</math> and <math>y</math>. What is the value of<cmath>(1\diamond(2\diamond3))-((1\diamond2)\diamond3)?</cmath> | |
+ | <math> \textbf{(A)}\ -2 \qquad | ||
+ | \textbf{(B)}\ -1 \qquad | ||
+ | \textbf{(C)}\ 0 \qquad | ||
+ | \textbf{(D)}\ 1 \qquad | ||
+ | \textbf{(E)}\ 2</math> | ||
[[2022 AMC 12B Problems/Problem 1|Solution]] | [[2022 AMC 12B Problems/Problem 1|Solution]] |
Revision as of 15:33, 17 November 2022
2022 AMC 12B (Answer Key) Printable versions: • AoPS Resources • PDF | ||
Instructions
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Contents
[hide]- 1 Problem 1
- 2 Problem 2
- 3 Problem 3
- 4 Problem 4
- 5 Problem 5
- 6 Problem 6
- 7 Problem 7
- 8 Problem 8
- 9 Problem 9
- 10 Problem 10
- 11 Problem 11
- 12 Problem 12
- 13 Problem 13
- 14 Problem 14
- 15 Problem 15
- 16 Problem 16
- 17 Problem 17
- 18 Problem 18
- 19 Problem 19
- 20 Problem 20
- 21 Problem 21
- 22 Problem 22
- 23 Problem 23
- 24 Problem 24
- 25 Problem 25
Problem 1
Define to be for all real numbers and . What is the value of
Problem 2
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Problem 3
How many of the first ten numbers of the sequence , , , ... are prime numbers?
Problem 4
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Problem 5
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Problem 6
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Problem 7
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Problem 8
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Problem 9
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Problem 10
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Problem 11
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Problem 12
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Problem 13
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Problem 14
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Problem 15
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Problem 16
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Problem 17
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Problem 18
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Problem 19
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Problem 20
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Problem 21
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Problem 22
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Problem 23
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Problem 24
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Problem 25
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