Difference between revisions of "2022 MMATHS Individual Round Problems/Problem 2"
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==Solution 1== | ==Solution 1== | ||
+ | The area of rectangle <math>BEHG</math> is <math>6 \cdot 4 = 24</math>. The area of triangle <math>BEF = \frac {8 \cdot 6}{2} = 24</math>. The area of rectangle <math>BDIF</math> is <math>3 \cdot = 24</math>. The area of triangle <math>DBG</math> is <math>\frac {4 \cdot 3}{2} = 6</math>. Add them all together to get <math>\boxed {78}</math>. | ||
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+ | ~Arcticturn |
Latest revision as of 21:13, 18 December 2022
Problem
Triangle has
and
. Points
and
are the reflections of
over
,
over
,
over
,
over
,
over
, and
over
, respectively. Find the area of hexagon
.
Solution 1
The area of rectangle is
. The area of triangle
. The area of rectangle
is
. The area of triangle
is
. Add them all together to get
.
~Arcticturn