Difference between revisions of "2023 AMC 8 Problems/Problem 18"
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~Star League (https://starleague.us) | ~Star League (https://starleague.us) | ||
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+ | ==Video Solution by OmegaLearn (Using Restrictive Counting)== | ||
+ | https://youtu.be/gIjhiw1CUgY |
Revision as of 20:52, 24 January 2023
Solution
We have directions going
right or
left. We can assign a variable to each of these directions. We can call going right 1 direction X and we can call going 1 left Y. We can build a equation of
. Where we have to limit the number of moves we do. We can do this by making more of our moves the
move turn then the
move turn. The first obvious step is to go some amount of moves in the → direction then subtract off in the ← direction to land on
. The least amount of
’s added to
to make a multiple of
is
as
. So now we have solved the problem as we just go
hops right, and just do 4 more hops left. Yielding
as our answer.
~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat, lpieleanu
Animated Video Solution
~Star League (https://starleague.us)