Difference between revisions of "2023 AMC 8 Problems/Problem 11"
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+ | ==Problem== | ||
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+ | NASA’s Perseverance Rover was launched on July <math>30,</math> <math>2020.</math> After traveling <math>292,526,838</math> miles, it landed on Mars in Jezero Crater about <math>6.5</math> months later. Which of the following is closest to the Rover’s average interplanetary speed in miles per hour? | ||
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+ | <math>\textbf{(A)}\ 6,000 \qquad \textbf{(B)}\ 12,000 \qquad \textbf{(C)}\ 60,000 \qquad \textbf{(D)}\ 120,000 \qquad \textbf{(E)}\ 600,000</math> | ||
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==Solution 1== | ==Solution 1== | ||
Since the answers are so far apart, we just need to compute the # of figures the answer contains. So by approximating all the values for the hourly rate we have <math>\frac{300,000,000}{5 * 30 * 30} \approx \frac{300,000,000}{5000} = 60,000</math> which is <math>\boxed{\text{(C)}60,000}</math> | Since the answers are so far apart, we just need to compute the # of figures the answer contains. So by approximating all the values for the hourly rate we have <math>\frac{300,000,000}{5 * 30 * 30} \approx \frac{300,000,000}{5000} = 60,000</math> which is <math>\boxed{\text{(C)}60,000}</math> |
Revision as of 00:36, 25 January 2023
Problem
NASA’s Perseverance Rover was launched on July After traveling miles, it landed on Mars in Jezero Crater about months later. Which of the following is closest to the Rover’s average interplanetary speed in miles per hour?
Solution 1
Since the answers are so far apart, we just need to compute the # of figures the answer contains. So by approximating all the values for the hourly rate we have which is
~apex304 and SohumUttamchandani
Solution 2
miles is extremely close to miles. We also know that months is equivalent to hours. Now, we can calculate the speed in miles per hour, which we find is about .
~MathFun1000
Video Solution (Animated)
~Star League (https://starleague.us)