Difference between revisions of "1985 AJHSME Problem 13"
Coolmath34 (talk | contribs) (Created page with "== Problem == If you walk for <math>45</math> minutes at a rate of <math>4 \text{ mph}</math> and then run for <math>30</math> minutes at a rate of <math>10\text{ mph,}</math...") |
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<math>\text{(A)}\ 3.5\text{ miles} \qquad \text{(B)}\ 8\text{ miles} \qquad \text{(C)}\ 9\text{ miles} \qquad \text{(D)}\ 25\frac{1}{3}\text{ miles} \qquad \text{(E)}\ 480\text{ miles}</math> | <math>\text{(A)}\ 3.5\text{ miles} \qquad \text{(B)}\ 8\text{ miles} \qquad \text{(C)}\ 9\text{ miles} \qquad \text{(D)}\ 25\frac{1}{3}\text{ miles} \qquad \text{(E)}\ 480\text{ miles}</math> | ||
− | == Solution == | + | ==In-depth Solution by BoundlessBrain!== |
+ | https://youtu.be/varobXGlcdU | ||
+ | |||
Distance is equal to rate multiplied by time: | Distance is equal to rate multiplied by time: | ||
<cmath>d = \frac{45}{60} \cdot 4 + \frac{30}{60} \cdot 10 = \boxed{8}.</cmath> | <cmath>d = \frac{45}{60} \cdot 4 + \frac{30}{60} \cdot 10 = \boxed{8}.</cmath> | ||
The answer is <math>\text{(B)}.</math> | The answer is <math>\text{(B)}.</math> |
Revision as of 15:58, 4 July 2023
Problem
If you walk for minutes at a rate of
and then run for
minutes at a rate of
how many miles will you have gone at the end of one hour and
minutes?
In-depth Solution by BoundlessBrain!
Distance is equal to rate multiplied by time:
The answer is