Difference between revisions of "2023 AMC 10B Problems/Problem 2"

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<math>\textbf{(A) }$46\qquad\textbf{(B) }$47\qquad\textbf{(C) }$48\qquad\textbf{(D) }$49\qquad\textbf{(E) }$50 </math>
 
<math>\textbf{(A) }$46\qquad\textbf{(B) }$47\qquad\textbf{(C) }$48\qquad\textbf{(D) }$49\qquad\textbf{(E) }$50 </math>
 
   
 
   
==Solution==
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==Solution 1==
  
 
Let the original price be <math>x</math> dollars.  
 
Let the original price be <math>x</math> dollars.  
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~Mintylemon66
 
~Mintylemon66
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==Solution 2==
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We can assign a variable <math>c</math> to represent the original cost of the running shoes. Next we set up the equation <math>80\%\cdot107.5\%\cdot c=43</math>. We can solve this equation for <math>c</math> and get <math>c=\boxed{\textbf{(E) }$50}</math>.
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~vsinghminhas

Revision as of 15:03, 15 November 2023

Problem

Carlos went to a sports store to buy running shoes. Running shoes were on sale, with prices reduced by $20\%$on every pair of shoes. Carlos also knew that he had to pay a $7.5\%$ sales tax on the discounted price. He had $$43$ dollars. What is the original (before discount) price of the most expensive shoes he could afford to buy?


$\textbf{(A) }$46\qquad\textbf{(B) }$47\qquad\textbf{(C) }$48\qquad\textbf{(D) }$49\qquad\textbf{(E) }$50$

Solution 1

Let the original price be $x$ dollars. After the discount, the price becomes $80\%x$ dollars. After tax, the price becomes $80\% \times (1+7.5\%) = 86\% x$ dollars. So, $43=86\%x$, $x=\boxed{\textbf{(E) }$50}.$

~Mintylemon66

Solution 2

We can assign a variable $c$ to represent the original cost of the running shoes. Next we set up the equation $80\%\cdot107.5\%\cdot c=43$. We can solve this equation for $c$ and get $c=\boxed{\textbf{(E) }$50}$.

~vsinghminhas