Difference between revisions of "2023 AMC 10B Problems/Problem 10"
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| − | First, note that since the rectangle covers 2 squares, we only need to guess squares that are not adjacent to any of our other guesses. There are only two ways to do this: one with <math>5</math> guesses, and one with <math>4</math>. Since the problem is asking for the minimum number, the answer is <math>4</math>. | + | First, note that since the rectangle covers 2 squares, we only need to guess squares that are not adjacent to any of our other guesses. There are only two ways to do this: one with <math>5</math> guesses, and one with <math>4</math>. Since the problem is asking for the minimum number, the answer is <math>\boxed{\text{(C) } 4}</math>. |
| − | + | ~yourmomisalosinggame (a.k.a. Aaron) | |
Revision as of 17:45, 15 November 2023
Solution 1
First, note that since the rectangle covers 2 squares, we only need to guess squares that are not adjacent to any of our other guesses. There are only two ways to do this: one with 
guesses, and one with 
. Since the problem is asking for the minimum number, the answer is 
.
~yourmomisalosinggame (a.k.a. Aaron)
