Difference between revisions of "2023 IOQM/Problem 10"

(Created page with "The sequence hanin≥0 is defined by a0 = 1, a1 = −4 and an+2 = −4an+1 − 7an , for n ≥ 0 . Find the number of positive integer divisors of a 2 50 − a49a51")
 
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The sequence hanin≥0 is defined by a0 = 1, a1 = −4 and an+2 = −4an+1 − 7an ,
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The [[sequence]] <math>\{a_n\}_{n\geq0}</math> is defined by <math>a_0 = 1</math>, <math>a_1 = -4</math>, and <math>a_{n+2} = -4a_{n+1} - 7a_n, \text{for } n \geq 0.
for n 0 . Find the number of positive integer divisors of a
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</math> Find the number of [[positive integer]] [[divisors]] of <math>a_{50}^2 - a_{49}a_{51}</math>.
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50 − a49a51
 

Latest revision as of 00:58, 21 November 2023

The sequence $\{a_n\}_{n\geq0}$ is defined by $a_0 = 1$, $a_1 = -4$, and $a_{n+2} = -4a_{n+1} - 7a_n, \text{for } n \geq 0.$ Find the number of positive integer divisors of $a_{50}^2 - a_{49}a_{51}$.