Difference between revisions of "2008 AMC 8 Problems/Problem 2"

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==Solution==
 
==Solution==
We can derive that <math>C=8</math>, <math>L=6</math>, <math>U=7</math>, and <math>E=2</math>. Therefore, the answer is <math>\boxed{\textbf{(A)}\ 8672}</math>
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We can derive that <math>C=8</math>, <math>L=6</math>, <math>U=7</math>, and <math>E=2</math>. Therefore, the answer is <math>\boxed{\textbf{(B)}\ 8672}</math>
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2008|num-b=1|num-a=3}}
 
{{AMC8 box|year=2008|num-b=1|num-a=3}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 22:32, 29 December 2023

Problem

The ten-letter code $\text{BEST OF LUCK}$ represents the ten digits $0-9$, in order. What 4-digit number is represented by the code word $\text{CLUE}$?

$\textbf{(A)}\ 8671 \qquad \textbf{(B)}\ 8672 \qquad \textbf{(C)}\ 9781 \qquad \textbf{(D)}\ 9782 \qquad \textbf{(E)}\ 9872$

Solution

We can derive that $C=8$, $L=6$, $U=7$, and $E=2$. Therefore, the answer is $\boxed{\textbf{(B)}\ 8672}$

See Also

2008 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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