Difference between revisions of "2002 AMC 12P Problems/Problem 2"
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The function <math>f</math> is given by the table | The function <math>f</math> is given by the table | ||
<cmath> | <cmath> | ||
− | \begin{tabular}{|c|c|c|c|c|c|} | + | \begin{tabular}{|c||c|c|c|c|c|} |
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x & 1 & 2 & 3 & 4 & 5 \\ | x & 1 & 2 & 3 & 4 & 5 \\ |
Revision as of 01:26, 30 December 2023
Problem
The function is given by the table
If and
for
, find
Solution
If , then
. Since
,
must be
to some factor of 6. Thus, there are four (3, 9, 27, 729) possible values of
.
See also
2002 AMC 12P (Problems • Answer Key • Resources) | |
Preceded by Problem 1 |
Followed by Problem 3 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.