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Difference between revisions of "Solution to Principle of Insufficient Reason Introductory Problem 1"
(→‎Olympaid problem)
 
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<math>\text{Principle of Insufficient Reason} \implies \text{max} ([\text{hexagon}])=[\text{Regular Hexagon}]=\boxed{\frac{3}{2} \sqrt{3}}</math>
 
<math>\text{Principle of Insufficient Reason} \implies \text{max} ([\text{hexagon}])=[\text{Regular Hexagon}]=\boxed{\frac{3}{2} \sqrt{3}}</math>
 
==Olympaid problem==
 
==Olympaid problem==
−
Principle of Insufficient Reason <math>\implies</math> the max of <math>e</math> is achieved when <math>a=b=c=d</math> so <cmath>4a+e=8</cmath> <cmath>4a^2+e^2=16</cmath>. Solving gives <math>e=\frac{16}{5}</math>
+
Principle of Insufficient Reason <math>\implies</math> the max of <math>e</math> is achieved when <math>a=b=c=d</math> so <cmath>4a+e=8</cmath> <cmath>4a^2+e^2=16</cmath> <cmath>\implies e=\frac{16}{5}</cmath>

Latest revision as of 23:10, 19 January 2024

Problem 1

$\text{Principle of Insufficient Reason} \implies \text{max} ([\text{hexagon}])=[\text{Regular Hexagon}]=\boxed{\frac{3}{2} \sqrt{3}}$

Olympaid problem

Principle of Insufficient Reason $\implies$ the max of $e$ is achieved when $a=b=c=d$ so \[4a+e=8\] \[4a^2+e^2=16\] \[\implies e=\frac{16}{5}\]

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