Difference between revisions of "2024 AMC 8 Problems/Problem 22"
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| − | There are about <math>\dfrac{1}{0.015}=\dfrac{200}{3}</math> "full circles" of tape, and with average circumference of <math>3\pi.</math> <math>\dfrac{200}{3}*3\pi=200\pi, </math> which means the answer is <math>600.</math> | + | There are about <math>\dfrac{1}{0.015}=\dfrac{200}{3}</math> "full circles" of tape, and with average circumference of <math>\dfrac{4+2}{2}\pi=3\pi.</math> <math>\dfrac{200}{3}*3\pi=200\pi, </math> which means the answer is <math>600.</math> |
Revision as of 15:56, 25 January 2024
Problem 22
Solution
There are about 
"full circles" of tape, and with average circumference of 
which means the answer is 
