Difference between revisions of "2024 AMC 8 Problems/Problem 10"
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This is a time period of <math>50</math> years, so we can expect the ppm to increase by <math>50*1.515=75.75~76</math>. | This is a time period of <math>50</math> years, so we can expect the ppm to increase by <math>50*1.515=75.75~76</math>. | ||
| − | <math>76+338=(B) \ | + | <math>76+338=\boxed{\textbf{(B)\ 414}}</math>. |
-ILoveMath31415926535 | -ILoveMath31415926535 | ||
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| + | ==Solution 1== | ||
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| + | For each year that has passed, the ppm will increase by <math>50</math>. In <math>2030</math>, the CO2 would have increased by <math>50\cdot 1.515 \approx 76,</math> so the total ppm of CO2 will be <math>76 + 338 = \boxed{\textbf{(B)\ 414}}.</math> | ||
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| + | -Benedict T (countmath1) | ||
==Video Solution 1 (easy to digest) by Power Solve== | ==Video Solution 1 (easy to digest) by Power Solve== | ||
Revision as of 13:56, 26 January 2024
Contents
Problem
In January 
the Mauna Loa Observatory recorded carbon dioxide (CO2) levels of 
ppm (parts per million). Over the years the average CO2 reading has increased by about 
ppm each year. What is the expected CO2 level in ppm in January 
? Round your answer to the nearest integer.
Solution 1
This is a time period of 
years, so we can expect the ppm to increase by 
.
.
-ILoveMath31415926535
Solution 1
For each year that has passed, the ppm will increase by . In , the CO2 would have increased by 
so the total ppm of CO2 will be 
-Benedict T (countmath1)
Video Solution 1 (easy to digest) by Power Solve
https://youtu.be/16YYti_pDUg?si=T3FZAZoeeL5NP3yR&t=411
