Difference between revisions of "2024 AMC 8 Problems/Problem 2"
Niuniumaths (talk | contribs) (→Video Solution 1 (easy to digest) by Power Solve) |
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~Dreamer1297 | ~Dreamer1297 | ||
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+ | ==Solution 3== | ||
+ | Convert all of them into the same demoninator of <math>1100</math>. We have <math>\frac{4400}{1100} + \frac{2750}{1100} + \frac{44}{1100} = \frac{7194}{1100} = \boxed{\textbf{(C) }6.54}</math> | ||
+ | ~andliu766 | ||
==Video Solution by NiuniuMaths (Easy to understand!)== | ==Video Solution by NiuniuMaths (Easy to understand!)== |
Revision as of 16:56, 26 January 2024
Contents
[hide]Problem
What is the value of the expression in decimal form?
Solution 1
We see , , and . Thus,
~MrThinker
Solution 2
We can simplify this expression into . Now, taking the common denominator, we get
~Dreamer1297
Solution 3
Convert all of them into the same demoninator of . We have ~andliu766
Video Solution by NiuniuMaths (Easy to understand!)
https://www.youtube.com/watch?v=Ylw-kJkSpq8
~NiuniuMaths
Video Solution 1 (easy to digest) by Power Solve
https://youtu.be/HE7JjZQ6xCk?si=4I0UO5oOVrC2vJep&t=29
Video Solution 2 by SpreadTheMathLove
https://www.youtube.com/watch?v=L83DxusGkSY
Video Solution by CosineMethod [🔥Fast and Easy🔥]
https://www.youtube.com/watch?v=NLoyzNyvFKU
See Also
2024 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.