Difference between revisions of "2024 AMC 8 Problems/Problem 2"
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==Video Solution by NiuniuMaths (Easy to understand!)== | ==Video Solution by NiuniuMaths (Easy to understand!)== | ||
− | https://www.youtube.com/watch?v= | + | https://www.youtube.com/watch?v=dQw4w9WgXcQ |
~NiuniuMaths | ~NiuniuMaths |
Revision as of 00:07, 1 February 2024
Contents
- 1 Problem
- 2 Solution 1
- 3 Solution 2
- 4 Solution 3
- 5 Solution 4(fastest)
- 6 Video Solution by Math-X (First fully understand the problem!!!)
- 7 Video Solution 1 (easy to digest) by Power Solve
- 8 Video Solution by NiuniuMaths (Easy to understand!)
- 9 Video Solution 2 by SpreadTheMathLove
- 10 Video Solution by CosineMethod [🔥Fast and Easy🔥]
- 11 See Also
Problem
What is the value of the expression in decimal form?
Solution 1
We see ,
, and
. Thus,
For this problem, a lot of people struggle to immediately think of this solution, and instead try to make all denominators the same which wastes a lot of time.
~MrThinker ~ Nivaar
Solution 2
We can simplify this expression into . Now, taking the common denominator, we get
~Dreamer1297
Solution 3
Convert all of them into the same demoninator of . We have
~andliu766
Solution 4(fastest)
Use 4400 as the common denominator.
-thebanker88
Video Solution by Math-X (First fully understand the problem!!!)
https://www.youtube.com/watch?v=dQw4w9WgXcQ ~Rick Atsley
Video Solution 1 (easy to digest) by Power Solve
https://www.youtube.com/watch?v=dQw4w9WgXcQ
Note: thiss link was made by @iamatinychildwhoisincapableofdoinganything,existentornonexistent
Video Solution by NiuniuMaths (Easy to understand!)
https://www.youtube.com/watch?v=dQw4w9WgXcQ
~NiuniuMaths
Video Solution 2 by SpreadTheMathLove
https://www.youtube.com/watch?v=L83DxusGkSY
Video Solution by CosineMethod [🔥Fast and Easy🔥]
https://www.youtube.com/watch?v=NLoyzNyvFKU
See Also
2024 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.