Difference between revisions of "2024 AIME I Problems/Problem 6"

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==Problem==
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An <math>8*8</math> grid is shown. Find the number of paths from the lower-left hand corner to the upper-right hand corner that consist of <math>16</math> grid movements and exactly four “turns.” [REWORD PLZ]
  
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==Solution==
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We divide the path into eight “<math>R</math>” movements and eight “<math>U</math>” movements. Five sections of alternative <math>RURUR</math> or <math>URURU</math> are necessary in order to make four “turns.” We use the first case and multiply by <math>2</math>.
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For <math>U</math>, we have seven ordered pairs of positive integers <math>(a,b)</math> such that <math>a+b=8</math>.
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For <math>R</math>, we subtract <math>1</math> from each section (as the minimum is <math>1</math>) and we use Stars and Bars to get <math>(7 \choose 5)=21</math>.
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Thus our answer is <math>7*21*2=\boxed{294}</math>.

Revision as of 13:30, 2 February 2024

Problem

An $8*8$ grid is shown. Find the number of paths from the lower-left hand corner to the upper-right hand corner that consist of $16$ grid movements and exactly four “turns.” [REWORD PLZ]

Solution

We divide the path into eight “$R$” movements and eight “$U$” movements. Five sections of alternative $RURUR$ or $URURU$ are necessary in order to make four “turns.” We use the first case and multiply by $2$.


For $U$, we have seven ordered pairs of positive integers $(a,b)$ such that $a+b=8$.

For $R$, we subtract $1$ from each section (as the minimum is $1$) and we use Stars and Bars to get $(7 \choose 5)=21$.


Thus our answer is $7*21*2=\boxed{294}$.