Difference between revisions of "1998 CEMC Gauss (Grade 7) Problems/Problem 6"
De-math-wiz (talk | contribs) m (→Solution) |
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879 | 879 | ||
x 492 | x 492 | ||
| + | ________ | ||
1,758 | 1,758 | ||
79,110 | 79,110 | ||
+351,600 | +351,600 | ||
| + | ________ | ||
=432,468 | =432,468 | ||
Therefore add 1+9+1+2 = 13, so (A) 13 is correct answer. | Therefore add 1+9+1+2 = 13, so (A) 13 is correct answer. | ||
Revision as of 16:16, 12 May 2024
Problem
In the multiplication question, the sum of the digits in the four boxes is:
[Multiply 
using long multiplication. Find the sum of the four numbers in the thousands place column.]
Solution
Multiplying, we find that the numbers in the thousands place column are 1, 9, 1, and 2 respectively. Adding yields a sum of 12, so the answer is 
-edited by coolmath34
If anyone knows the LaTeX to show long multiplication, any help would be appreciated.
-edited by De-math-wiz
Solution
While doing the long multiplication the numbers in the thousand place are 1, 9, and 2 respectively. When added the sum is 13, so the answer is (A) 13
879x492 = 432,468
879 x 492
________
1,758 79,110
+351,600 ________ =432,468
Therefore add 1+9+1+2 = 13, so (A) 13 is correct answer.
