Difference between revisions of "1970 AMC 12 Problems/Problem 2"
(New page: A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is) |
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| + | == Problem == | ||
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A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is | A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is | ||
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| + | <math> \mathrm{(A) \ } -h\qquad \mathrm{(B) \ } 0\qquad \mathrm{(C) \ } h\qquad \mathrm{(D) \ } 2h</math> | ||
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| + | <math>\mathrm{(E) \ } h^3</math> | ||
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| + | == Solution == | ||
Revision as of 12:29, 9 January 2008
Problem
A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is
