Difference between revisions of "1970 AMC 12 Problems/Problem 2"
(→Problem) |
|||
| Line 3: | Line 3: | ||
A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is | A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is | ||
| − | <math> \mathrm{(A) \ } | + | <math> \mathrm{(A) \ } pi/4\qquad \mathrm{(B) \ } 0\qquad \mathrm{(C) \ } h\qquad \mathrm{(D) \ } 2h</math> |
<math>\mathrm{(E) \ } h^3</math> | <math>\mathrm{(E) \ } h^3</math> | ||
== Solution == | == Solution == | ||
Revision as of 11:30, 9 January 2008
Problem
A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is
