Difference between revisions of "1990 USAMO Problems/Problem 5"
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− | + | An acute-angled triangle <math>ABC</math> is given in the plane. The circle with diameter <math>\, AB \,</math> intersects altitude <math>\, CC' \,</math> and its extension at points <math>\, M \,</math> and <math>\, N \,</math>, and the circle with diameter <math>\, AC \,</math> intersects altitude <math>\, BB' \,</math> and its extensions at <math>\, P \,</math> and <math>\, Q \,</math>. Prove that the points <math>\, M, N, P, Q \,</math> lie on a common circle. | |
== Solution == | == Solution == | ||
{{solution}} | {{solution}} | ||
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{{alternate solutions}} | {{alternate solutions}} |
Revision as of 12:15, 10 February 2008
Problem
An acute-angled triangle is given in the plane. The circle with diameter
intersects altitude
and its extension at points
and
, and the circle with diameter
intersects altitude
and its extensions at
and
. Prove that the points
lie on a common circle.
Solution
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Alternate solutions are always welcome. If you have a different, elegant solution to this problem, please add it to this page.