Difference between revisions of "2007 Alabama ARML TST Problems/Problem 6"
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==Solution== | ==Solution== | ||
− | + | <math>r</math> satisfies <math>r^2+r+6=0</math>. Thus, <math>r^3+2r^2+7r+17 = (r^3+r^2+6r)+(r^2+r+6)+11 =</math> <math>(r+1)(r^2+r+6)+11 = (r+1)(0)+11 = 11</math>. | |
==See also== | ==See also== | ||
{{ARML box|year=2007|state=Alabama|num-b=5|num-a=7}} | {{ARML box|year=2007|state=Alabama|num-b=5|num-a=7}} |