Difference between revisions of "2001 IMO Shortlist Problems/N6"

(This should have been combinatorics, and how did it get to the shortlist anyways???)
(Undo revision 28160 by 1=2 (Talk))
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== Solution ==
 
== Solution ==
The biggest pairwise sum is <math>24999+25000=49999</math>, and there are <math>\binom{100}{2}=50050</math> sums. Thus by the [[Pigeonhole Principle]], there must be at least two sums which are equal.
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== Resources ==
 
== Resources ==

Revision as of 08:31, 6 October 2008

Problem

Is it possible to find 100 positive integers not exceeding 25,000, such that all pairwise sums of them are different?

Solution

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Resources