Difference between revisions of "1986 AJHSME Problems/Problem 15"

(Solution)
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<math>90 \times 20\% = 90 \times \frac{2}{10} = 9 \times 2 = 18</math>
 
<math>90 \times 20\% = 90 \times \frac{2}{10} = 9 \times 2 = 18</math>
  
Thus it would cost <math> \</math>18$ dollars!
+
Thus it would cost <math> \</math>18 dollars!
  
 
==See Also==
 
==See Also==
  
 
[[1986 AJHSME Problems]]
 
[[1986 AJHSME Problems]]

Revision as of 18:18, 24 January 2009

Problem

Sale prices at the Ajax Outlet Store are $50\%$ below original prices. On Saturdays an additional discount of $20\%$ off the sale price is given. What is the Saturday price of a coat whose original price is <dollar/>$180$?

$\text{(A)}$ <dollar/>$54$

$\text{(B)}$ <dollar/>$72$

$\text{(C)}$ <dollar/>$90$

$\text{(D)}$ <dollar/>$108$

$\text{(D)}$ <dollar/>$110$

Solution

First we need to do the first discount, which, at Ajax Outlet Store, would be there any day of the week.

$180 \times 50\% = 180 \times \frac{1}{2} = 90$

Then we factor in the $20\%$ discount.

$90 \times 20\% = 90 \times \frac{2}{10} = 9 \times 2 = 18$

Thus it would cost $$18 dollars!

See Also

1986 AJHSME Problems